Key Wheeling in a Trifecta Bet
Key-wheeling in a trifecta bet means selecting a key horse in a fixed position, usually first, and wheeling any number of other horses in multiple combinations to finish in the remaining positions, usually second and third. If the 1 is key-wheeled with the 2, 3, and 5, the combinations of 1-2-3, 1-2-5, 1-3-2, 1-3-5, 1-5-2, and 1-5-3 are covered. As long as the 1 is the winner and any combination of the numbers 2, 3, and 5 are second and third, the key-wheeled wager is a winner. The more numbers used with the key-wheeled selection, the greater the number of possibilities covered. However, the more numbers used, the greater the cost to cover the wager.
# of choices | # of combinations | $ amount of bet | Cost of bet |
2
|
2
|
$1 ($2)
|
$2 ($4)
|
3
|
6
|
$1 ($2)
|
$6 ($12)
|
4
|
12
|
$1 ($2)
|
$12 ($24)
|
5
|
20
|
$1 ($2)
|
$20 ($40)
|
6
|
30
|
$1 ($2)
|
$30 ($60)
|
7
|
42
|
$1 ($2)
|
$42 ($84)
|
8
|
56
|
$1 ($2)
|
$56 ($112)
|
9
|
72
|
$1 ($2)
|
$72 ($144)
|
10
|
90
|
$1 ($2)
|
$90 ($180)
|
11
|
110
|
$1 ($2)
|
$110 ($220)
|
12
|
132
|
$1 ($2)
|
$132 ($264)
|
13
|
156
|
$1 ($2)
|
$156 ($312)
|
A simple rule to remember to compute the cost of a key-wheeled trifecta wager would be as follows: the number of horses to be boxed with the keyed selection MULTIPLIED by the next lowest number MULTIPLIED by the dollar amount of the wager. EXAMPLE: A key-wheeled trifecta using 4 choices with the key-wheeled selection for $2 would be computed 4 ( the number of horses boxed with the key-wheeled selection) x 3 (next lowest number) x 2 (dollar amount of wager) = $24.